tag:blogger.com,1999:blog-203851052017-06-21T19:20:59.267-07:00Math 7-437-43 This is your home on the Internet. Use it to communicate with one another and expand your knowledge of mathematics and the world around youMr. Reecehttp://www.blogger.com/profile/10256211127811144005noreply@blogger.comBlogger152125tag:blogger.com,1999:blog-20385105.post-1158193071948649172006-09-13T17:12:00.000-07:002006-09-13T17:17:52.280-07:00Hi Mr. Reece<strong><span style="font-family:georgia;color:#3333ff;">Hi Mr.Reece if you go on your blog can you respond to this??????????? This year I am in Mr Penners class room which is 8-16. I am doing very well and I had a great summer how about you???????????</span></strong>Candynoreply@blogger.com2tag:blogger.com,1999:blog-20385105.post-1153619560079985052006-07-22T18:49:00.000-07:002006-07-22T18:52:40.333-07:00hey everyonehey this is janna and i hope everyone's having an AWESOME !!!! summer. cool kay byeJanna_09noreply@blogger.com1tag:blogger.com,1999:blog-20385105.post-1149643512298034792006-06-06T18:24:00.000-07:002006-06-06T18:25:12.943-07:00Kim's Growing Post for June 6th<span style="color:#3333ff;">Question 1: Formulas. </span><span style="color:#6666cc;">We've learned how to write algebraic equations in the form of <strong>mx + b = y</strong></span><br /><span style="color:#6666cc;">Convert these two sentences into algebraic using the above formula. </span><br /><br /><span style="color:#cc33cc;"><strong><em>m: change or coefficient</em></strong></span><br /><strong><em><span style="color:#cc33cc;">b: constant or start</span></em></strong><br /><span style="color:#cc33cc;"><strong><em>y: solution</em></strong></span><br /><br /><span style="color:#6666cc;"><span style="color:#3333ff;">Sentence 1:</span> Scott is 2 years older than Donald who turns 12 on June 21st 2006. Write this sentence in the format of <strong>mx + b = y, </strong>then convert it into an expression which allows us to figure out the age of Scott. </span><span style="color:#cc33cc;">Scott is 13 years old and Donald will be 12 years old.</span><br /><span style="color:#6666cc;"></span><br /><br /><br /><br /><div align="center"><span style="color:#cc33cc;">2 + b = y </span></div><div align="center"><span style="color:#cc33cc;">2 + 11 = y</span></div><div align="center"><span style="color:#cc33cc;">2 + 11 = 13</span></div><div align="center"></div><div align="left"><span style="color:#3333ff;">Sentence 2: <span style="color:#6666cc;">Elizabeth has $200 in her savings account. She makes $40 every two weeks babysitting for her next door neighbours. If Elizabeth saves all of her money solve for how much money she will have in one year?</span> </span><span style="color:#cc33cc;">Elizabeth will have a total of $1160 in one year.</span></div><div align="left"><span style="color:#3333ff;"></span></div><div align="center"><span style="color:#cc33cc;">$40n + $200 = y</span></div><div align="center"><span style="color:#cc33cc;">$40(24) + $200 = $1160</span></div><div align="center"><span style="color:#cc33cc;"></span></div><div align="left"><span style="color:#3333ff;">Question 2: Creation. </span><span style="color:#6666cc;">You need to create two questions for your classmates that cover different concepts (ex: T-charts, patterns, equations, graphs etc.) that you have learned in this unit on Algebra. You then need to show how to solve the questions. Your mark will be based upon the lvl of question's difficulty, and the effort put into your answer.</span></div><div align="left"><span style="color:#6666cc;"></span></div><div align="left"><span style="color:#6666cc;"></span></div><div align="left"><span style="color:#6666cc;"><span style="color:#ff0000;">Bobby has $500 dollars in his bank account and he earns $50 every month. His friend John has $250 in his bank account and he earns $75 every month. How much will Bobby and John have in their bank account in one year and who will have the most amount of money?</span> </span><span style="color:#cc33cc;">Bobby will have a total of $1100 <span style="color:#ff6600;">and</span> <span style="color:#009900;">John will have a total of $1150</span> </span><span style="color:#ffcc00;">and John will have $50 more than Bobby.</span></div><div align="left"><span style="color:#cc33cc;"></span></div><div align="center"><span style="color:#cc33cc;"></span></div><div align="center"><span style="color:#cc33cc;"></span></div><div align="center"><span style="color:#cc33cc;">$50x + $500 = y</span></div><div align="center"><span style="color:#cc33cc;">$50(12) + $500 = $1100</span> </div><div align="center"></div><div align="center"></div><div align="center"><span style="color:#009900;"></span></div><div align="center"><span style="color:#009900;">$75x + $250 = y</span></div><div align="center"><span style="color:#009900;">$75(12) + $250 = $1150</span></div><div align="left"></div><div align="left"><br /><a href="http://photos1.blogger.com/blogger/1619/2126/1600/Math7.0.jpg"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/Math7.0.jpg" border="0" /></a><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%208.jpg"><img style="FLOAT: right; MARGIN: 0px 0px 10px 10px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%208.jpg" border="0" /></a><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%207.0.jpg"></a><br /></div><strong><em><span style="color:#6666cc;"></span></em></strong><p><span style="color:#cc33cc;"><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%207.0.jpg"></a></span></p><br /><br /><br /><br /><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><span style="color:#cc33cc;"><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%207.0.jpg"></a></span></p><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%209.jpg"><img style="FLOAT: right; MARGIN: 0px 0px 10px 10px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%209.jpg" border="0" /></a><br /><br /><p><span style="color:#cc33cc;"><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%207.0.jpg"><img style="FLOAT: right; MARGIN: 0px 0px 10px 10px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%207.0.jpg" border="0" /></a></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p><span style="color:#ff0000;">One day, Sandy and Lina decided to save money and buy a walkman for $150 and share it with each other since they were sisters. Sandy had $60 in her bank account and she would add $10 everyday for 10 days while Lina had $120 in her bank account but she would spend $10 everyday for herself for 10 days. On the 10th day, will Lina and Sand</span><span style="color:#ff0000;">y have enough money to buy the $150 walkman and have leftover money? Or will they have to save more to buy a walkman? </span><span style="color:#cc33cc;">Sandy and Lina will have enough money in total to buy the $150 walkman and have $40 leftover.</span></p><p align="center">Sandy: 10x + 60 = y</p><p align="center">10(11) + 60 = 170</p><p align="center">Lina: -10x + 120 = y </p><p align="center">-10(10) + 120 = 20 </p><p></p><p><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%202.3.jpg"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%202.3.jpg" border="0" /></a><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%202.2.jpg"><img style="FLOAT: right; MARGIN: 0px 0px 10px 10px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%202.2.jpg" border="0" /></a></p><p align="left"></p><p align="left"></p><p align="left"></p><p align="left"></p><p align="left"></p><p align="left"></p><p align="left"></p><p align="left"></p><p align="left"><span style="color:#3333ff;">Question 3: Reflection. </span><span style="color:#6633ff;">You need to look back at the chart that we filled out during the first day of the unit. This is the chart where you coloured a topic red, yellow or green. You now need to pick one concept that you coloured yellow or red and reflect in words what new skill/idea that you have learned on this topic.</span></p><p align="left"><span style="color:#cc33cc;">Can I use my words to create an algebraic formula?</span></p><p align="left">I coloured this in red because I didn't know how to create a algebraic formula. So if I didn't know how to make one, I would probably not be able to make one from a T-Chart or use an algebraic formula to solve for an unknown. It was easier to make a formula when Mr.Reece had taught us how and it was helping me solve an unknown and make a formula by using a T-Chart.</p><p align="left"><span style="color:#3333ff;">Question 4: Preparing for the final exam. </span><span style="color:#6633ff;">You need to think about the year that has past in mathematics and decide which topic is your weakest, and what you need to learn duriong class review in order to prepare yourself for the final exam. It is not enough to say fractions, instead pick your weakest area of fractions, say the subtraction or fractions, and give an example of what you don't understand. </span></p><p align="left"><span style="color:#cc33cc;">My weakest topic is probably algebra. In algebra, there are always some questions that I can't figure out how to solve the unknown. But as Mr.Reece is teaching us, I am beginning to find it more easy little at a time and will be able to solve it. I also know that when the higher the grade i'm in, the harder the level of mathematics are and the harder the questions in algebra. (eaxample: -50x + 2o6 = y)</span></p><p align="left">KIM-THANH VO ROOM 7-43</p><p align="left"></p></span>Smiiliieshttp://www.blogger.com/profile/04196539918571169884noreply@blogger.com9tag:blogger.com,1999:blog-20385105.post-1149551650899575892006-06-05T15:39:00.000-07:002006-06-05T16:54:11.280-07:00My Growing Post<span style="color:#3333ff;"><span style="color:#ff0000;">Question 1: Formulas. We've learned how to write algebraic equations in the form of mx+b=y. Convert these two sentences into algebraic equations using the above formula.<br /><br />m - coefficient (change)<br /><br />x - variable<br /><br />b - constant (start)<br /><br />y - solution (answer)</span><br /><br /><span style="color:#33ffff;">Sentence 1: Scott is 2 years older than Donald who turns 12 on June 21st 2006. Write this sentence in the format mx+b=y, then convert it into an expression which allows us to figure out the age of Scott.<br /><br />2+d=s<br />2+11=13<br /></span><br /><span style="color:#33ff33;">Sentence 2: Elizabeth has $200 in her savings account. She makes $40 every two weeks babysitting for her next door neighbours. If Elizabeth saves all of her money solve for how much money she will have in one year.<br /><br />40+200e=<br />40 +200(26)=5240<br /></span><br /><span style="color:#cc33cc;">Question 2: Creation. You need to create two questions for your classmates that cover different concepts (ex: T-Charts, patterns, equations, graphs etc.) that you have learned in this unit on Algebra. You then need to show how to solve the questions. Your mark will be based upon the level of questions difficulty, and the effort put into your answer.<br /></span><br />There are 500 chocolate muffins for sale at the bake sale. If there were 50 customers and the each got the same amount how many muffins did each customer get?<br /><br />500/50=n<br />n=10<br /><br /></span><span style="color:#9999ff;">There are 12 dentists and 48 toothbrushes. How many toothbrushes does each dentist get?</span><br /><span style="color:#9999ff;"></span><br /><span style="color:#9999ff;">48/12=n</span><br /><span style="color:#9999ff;">n=4</span><br /><span style="color:#3333ff;"></span><br /><span style="color:#ff6600;">Question 3: Reflection. You need to look back at the chart that we filled out during the first day of the unit. This is the chart where you coloured a topic red. yellow or green. You now need to pick one concept that you coloured yellow or red and reflect in words what new skill/idea you have learned on this topic.</span><br /><span style="color:#3333ff;"></span><br /><span style="color:#009900;">Can I create a T-Chart for my pattern?</span><br /><span style="color:#009900;">This topic I coloured red because I did not get how to do that.</span><br /><span style="color:#009900;">Now I can easily do that because it is really easy now that I know what I am doing. I learned that you can solve a pattern by using a T-Chart.</span><br /><span style="color:#3333ff;"></span><br /><span style="color:#990000;">Question 4: Preparing for the final exam. You need to think about the year that has past in mathematics and decide which topic is your weakest, and what you need to learn during class reveiw in order to prepare yourself for the final exam. It is not enough to say fractions, instead pick your weakest area of fractions, say the subtraction of fractions, and give an example of what you don't understand.</span><br /><span style="color:#3333ff;"></span><br /><span style="color:#663366;">My weakest topic is fractions. Inside fractions I have trouble multipling fractions. I have always had trouble with fractions.</span><br /><span style="color:#663366;"></span><br /><span style="color:#663366;">Example: 1/4 x 3/4</span><br /><span style="color:#663366;"></span><br /><span style="color:#ffcc66;">Kendra 7-43</span>Fang_the_Barbarianhttp://www.blogger.com/profile/07926464780699354515noreply@blogger.com4tag:blogger.com,1999:blog-20385105.post-1149474953509205202006-06-04T17:57:00.000-07:002006-06-06T06:37:03.243-07:00My Growing post<span style="font-family:georgia;font-size:180%;color:#ff0000;">1. m - coefficient ( change )</span><br /><span style="font-family:georgia;font-size:180%;color:#ff0000;">x - variable </span><br /><span style="font-size:180%;color:#ff0000;">b- constant ( start )</span><br /><span style="font-family:georgia;font-size:180%;color:#ff0000;">y - solution ( answer )</span><br /><span style="font-size:180%;color:#ff0000;"></span><br /><span style="font-size:180%;color:#ff0000;">S1. 2+N=s</span><br /><span style="font-size:180%;color:#ff0000;">2+11=13</span><br /><span style="font-size:180%;color:#ff0000;"></span><br /><span style="font-size:180%;color:#ff0000;">S2. 40+200N=</span><br /><span style="font-size:180%;color:#ff0000;">40+200(26)=5240</span><br /><span style="font-size:180%;color:#ff0000;">Elizabeth will have $5240 in her acount at the end of the year.</span><br /><span style="font-size:180%;color:#ff0000;"></span><br /><span style="font-size:180%;color:#ff0000;">2. <span style="color:#3333ff;">There are 156 cookies in a jar and Heather ate 4 a day. How many cookies would be left in the jar at the end of the month which has 30 days?</span></span><br /><span style="font-size:180%;color:#ff0000;">4/156C=</span><br /><span style="font-size:180%;color:#ff0000;">C = 39</span><br /><span style="font-size:180%;color:#ff0000;"></span><br /><span style="font-size:180%;color:#ff0000;"></span><br /><span style="font-size:180%;color:#3333ff;">T</span><span style="font-size:180%;color:#3333ff;">here are 20 Police Officers and 5 dozen doughnuts. How many doughnuts were left for the next day?</span><br /><span style="font-size:180%;color:#3333ff;"><span style="color:#ff0000;">20/5P=</span></span><br /><span style="font-size:180%;color:#ff0000;">P = 4</span><br /><span style="font-size:180%;color:#ff0000;"></span><br /><span style="font-size:180%;color:#ff0000;">3. <span style="color:#3333ff;">Can I use my words to create an Algebraic Formula?</span></span><br /><span style="font-size:180%;color:#ff0000;">I coloured this topic red because at the begining of the year I didn't understand how to do it. Now I can make an Algebraic Formula with words and it will make sence.</span><br /><span style="font-size:180%;color:#ff0000;"></span><br /><span style="font-size:180%;color:#ff0000;">4. My weakest topic in math is doing Area and Circumference of a Circle, Triangle and Rectangle. I have trouble getting the answers for them.</span><br /><span style="font-size:180%;color:#ff0000;">Example:</span><br /><span style="font-size:180%;color:#ff0000;"></span><a href="http://photos1.blogger.com/blogger/4117/2103/1600/cts.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4117/2103/320/cts.jpg" border="0" /></a><br /><br /><div align="center"><span style="font-size:180%;color:#ff6600;">Thank-you Mr.Reece</span></div>Candynoreply@blogger.com9tag:blogger.com,1999:blog-20385105.post-1149464706076382672006-06-04T16:24:00.000-07:002006-06-06T10:48:29.286-07:00Janna's Growing Post for June 6th<strong>Question 1:</strong> Formulas. We’ve learned how to write algebraic equations in the form of<br />mx + b = y. Convert these two sentences into algebraic equations using the above formula. <span style="color: rgb(204, 51, 204);"><br /></span><span style="color: rgb(204, 51, 204);"><br />m - coefficient ( change )<br />x - variable<br />b - constant ( start )<br />y - solution<br /><br /><span style="color: rgb(0, 0, 0);"><strong>Sentence 1.</strong> Scott is 2 years older than Donald who turns 12 on June 21st 2006. Write this sentence in the format of mx + b = y, then convert it into an expression which allows us to figure out the age of Scott. </span><br />Scott = Donald + 2<br /><span style="color: rgb(204, 51, 204);">Scott = 11 + 2<br />Scott = 13<br /><br />N + 2 = 13 N = 11 which is Donalds age since he has not yet turned 12. <br /></span><br /><strong><span style="color: rgb(0, 0, 0);">Sentence 2.</span></strong> <span style="color: rgb(0, 0, 0);">Elizabeth has $200 in her savings account. She makes $40 every two weeks babysitting for her next door neighbours. If Elizabeth saves all of her money solve for how much money she will have in one year?<br /></span><br />40p + 200 = 1240<br /> - 200 - 200<br /> ____ ____<br /></span> 0 1040<br /> <br /> 40p = 1040<br /> <br /><strong>Question 2:</strong> Creation. You need to create two questions for your classmates that cover different concepts (ex: T-Charts, patterns, equations, graphs etc.) that you have learned in this unit on Algebra. You then need to show how to solve the questions. Your mark will be based upon the level of question’s difficulty, and the effort put into your answer.<br /><br />Question 3: Reflection. You need to look back at the chart that we filled out during the first day of the unit. This is the chart where you coloured a topic red, yellow or green. You now need to pick one concept that you coloured yellow or red and reflect in words what new skill/idea that you have learned on this topic.<br /><br />Question 4: Preparing for the final exam. You need to think about the year that has past in mathematics and decide which topic is your weakest, and what you need to learn during class review in order to prepare yourself for the final exam. It is not enough to say fractions, instead pick your weakest area of fractions, say the subtraction of fractions, and give an example of what you don’t understand.Janna_09noreply@blogger.com1tag:blogger.com,1999:blog-20385105.post-1149166395101863332006-06-01T05:42:00.000-07:002006-06-01T06:06:08.480-07:00Growing Post<span style="color: rgb(204, 102, 0); font-weight: bold; font-style: italic;">Question 1: What is the difference between an algerbraic expression and an equation (Hint: One contains this and the other doesn't)? Give an example of both an expression and an equation.</span> <span style="color: rgb(204, 102, 0);"><br /><br />An Algebraic expression is when you combine numbers, operatives, and/or free variables and bound variables. You get to choose the variable in an algebraic expression. An example: 5A X 6.</span> <span style="color: rgb(204, 102, 0);">In Algebraic equation, the variable is already given. There are two types of equations (from my knowledge), one step; 3E - 6 = 9, and two step; 3N = 1N +10. An example of an equation; 3H - 5 = 10. H = 5.</span><br /><br /><span style="color: rgb(102, 0, 204); font-style: italic; font-weight: bold;">Question 2: What is a variable and why do we use one in algebra?</span> <span style="color: rgb(102, 0, 204);"><br /><br /><br />Variables are letters that represent the unknown, able to change. Variables are often contrasted with constants, which are known and unchangning.</span> <span style="color: rgb(102, 0, 204);">We use variables because Algebra is a method of finding the unknown.</span><br /><span style="color: rgb(51, 204, 0);"><span style="font-style: italic; font-weight: bold;"><br /><br />Question 3: Solve for N</span><br /></span><span style="color: rgb(51, 204, 0);"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/1831/2100/1600/GrowingPost4%282%29.0.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/1831/2100/320/GrowingPost4%282%29.0.jpg" alt="" border="0" /></a><br /></span><span style="color: rgb(51, 204, 0);">To solve the first question, you need to figure out what a triangle equals on the first scale.</span> <span style="color: rgb(51, 204, 0);">First, take away four circles (each square equals two circles), which leaves five circles. Since there were five circles left, the triangle equals five circles.</span> <span style="color: rgb(51, 204, 0);"><br />To solve the second question, you need to figure out the value of the two N's.</span> <span style="color: rgb(51, 204, 0);">First, add the squares and triangles together. The total of the squares and triangles, together, was 22 circles. Then divide the 22 circles by 2. The answer was 11. Each N equals 11 circles.</span><br /><br /><br /><span style="color: rgb(102, 102, 204); font-style: italic; font-weight: bold;">Question 4: Solve the following equations. Show all of the steps that are needed.</span> <span style="color: rgb(102, 102, 204);"><br /><br />A) 3n+4n+7=2n+12</span><br /><span style="color: rgb(102, 102, 204);">3N + 4N - 2N = 12 - 7</span><br /><span style="color: rgb(102, 102, 204);">5N = 5</span> <span style="color: rgb(102, 102, 204);"><br />N=1</span> <span style="color: rgb(102, 102, 204);"><br /><br />B) 8n-(4+9)=11</span> <span style="color: rgb(102, 102, 204);"><br />8N = 13 + 11</span> <span style="color: rgb(102, 102, 204);"><br />13 + 11 = 24</span> <span style="color: rgb(102, 102, 204);"><br />8N = 24</span> <span style="color: rgb(102, 102, 204);"><br />N = 3</span><span style="color: rgb(102, 102, 204);"><br />C) (8-3)n+7n+8= 4n + 40</span><br /><span style="color: rgb(102, 102, 204);">5N + 7N + 8= 4N + 40</span> <span style="color: rgb(102, 102, 204);"><br />5N + 7N - 4N = 40 - 8</span> <span style="color: rgb(102, 102, 204);"><br />8N = 32</span> <span style="color: rgb(102, 102, 204);"><br />N = 4 </span><br /><br /><span style="color: rgb(204, 0, 0); font-weight: bold; font-style: italic;">Question 5: For this question you need to create a T-Chart and a graph to plot your data from this question onto.</span> <span style="color: rgb(204, 0, 0); font-weight: bold; font-style: italic;"><br />You are having a race against your friend, except you are on foot and he is on his bike. Your both know that if you are on a bike you will be faster so your friend gives you a head start of 3 minutes. If you can run 400m per minute, and your friend can bike 700m per minute, who will be the first to make it to the </span><span style="color: rgb(204, 0, 0);"><span style="font-weight: bold; font-style: italic;">finish line 2000m away?</span><br />The runner will finish in five minutes, the bicyclist will finish in six minutes, therefore the runner winning.</span><span style="color: rgb(204, 0, 0); font-weight: bold; font-style: italic;"><br /></span><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/1831/2100/1600/Growing%20Post%203.0.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/1831/2100/320/Growing%20Post%203.0.jpg" alt="" border="0" /></a><span style="color: rgb(204, 0, 0); font-weight: bold; font-style: italic;"><br /></span><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/1831/2100/1600/Growing%20Post%202.jpg"><span style="color: rgb(204, 0, 0); font-weight: bold; font-style: italic;"></span></a><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/1831/2100/1600/Growing%20Post.0.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/1831/2100/320/Growing%20Post.0.jpg" alt="" border="0" /></a><span style="color: rgb(204, 0, 0); font-weight: bold; font-style: italic;"><br /><br /></span><br /><span style="color: rgb(204, 0, 0); font-weight: bold; font-style: italic;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/1831/2100/1600/Growing%20Post%202.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/1831/2100/320/Growing%20Post%202.jpg" alt="" border="0" /></a></span>Ariahttp://www.blogger.com/profile/12976271291206028698noreply@blogger.com2tag:blogger.com,1999:blog-20385105.post-1148952471242525052006-05-29T18:27:00.000-07:002006-06-03T09:51:50.656-07:00Kim's growing Post for May 29<span style="color:#cc0000;"><span style="color:#3333ff;">Question 1.</span><br /></span><span style="color:#ff0000;">What is the difference between an algebraic expression and an equation (hint:one contains this and the other other doesn't?)<br /></span><br /><span style="color:#cc33cc;">The difference bewteen an <span style="color:#ff6600;">algebraic expression</span> and an <span style="color:#ff6600;">equation</span> is that the <span style="color:#ff6600;">algebraic expression</span> has not given the <span style="color:#339999;">value of the variable</span> and the <span style="color:#ff6600;">equation</span> has already given us </span><span style="color:#339999;">the value of the variable.</span> <span style="color:#33cc00;"><span style="color:#009900;">(example:)</span><br /></span><span style="color:#33cc00;">expression: 10 + 5n = the answer<br />equation: 10 + 5(3) = </span><span style="color:#000000;">45</span><br /><br /><span style="color:#3333ff;">Question 2.<br /></span><span style="color:#ff0000;">What is a variable and why do we use one in algebra.<br /></span><br /><span style="color:#cc33cc;">A variable represents the unknown number. We use a variable in algebra because the main thing about algebra is to find the unknown answer and since the variable is the unknown number, we have to solve the variable.</span><span style="color:#ff6600;"> (And if you have solved the variable, it makes it a whole lot easier to solve the equation.)<br /><br /></span><span style="color:#3333ff;">Question 3.<br /></span><span style="color:#ff0000;">Solve for N.</span><br /><br /><span style="color:#cc33cc;"><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%204.jpg"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%204.jpg" border="0" /></a><br /></span><span style="color:#cc33cc;"><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /></span><br /><br /><br /><br /><span style="color:#ff6600;">I need to solve how much the triangular equals to solve the question. After that, I need to solve how much the 2 N's equal to.</span><br /><span style="color:#cc33cc;"><span style="color:#cc9933;">Solving for first scale:</span> Since a square means 2 circles <span style="color:#000000;">and a circle means 1, </span>and the left side of the scale in this diagram has 2 squares, that means 4 circles <span style="color:#000000;">or 4 </span>in all. So I take 4 circles away from the right hand of the scale, I will end up having only 5 circles left and a triangle. So that means a triangle is equal to 5 circles. </span><br /><span style="color:#cc33cc;"><span style="color:#cc9933;">Solving for second scale:</span> Since I have already solved the value of the triangle<span style="color:#000000;"> and I know what the value of the circle and the square is, I will be able to solve the value of the 2 N's easily.</span> First I would have to add all the squares and triangles on the right hand of the scale, and it would come out of a total of 22 circles <span style="color:#000000;">or 22 </span><span style="color:#ff6600;">(since a triangle represents 5 circles and a square represents 2 circles.)</span> Now I will have to divide the number 22 in half <span style="color:#ff6600;">(because there are 2 Ns)</span> and I will get 11. So the value of each N will be 11. The total value of both Ns is 22 circles.</span><br /><span style="color:#cc33cc;"></span><br /><span style="color:#3333ff;">Question 4.</span><br /><span style="color:#ff0000;">Solve the following equations. Show all of the steps that are needed.</span><br /><span style="color:#ff0000;"></span><br /><span style="color:#ff6600;">a) 3n + 4n + 7 = 2n + 12</span><br /><span style="color:#cc33cc;">3n + 4n - 2n = 12 - 7</span><br /><span style="color:#cc33cc;">5n = 5</span><br /><span style="color:#cc33cc;">n = 5/5 = 1</span><br /><span style="color:#cc33cc;">n = 1</span><br /><span style="color:#cc33cc;"></span><br /><span style="color:#ff6600;">b) 8n - (4 + 9) = 11</span><br /><span style="color:#ff6600;"></span><span style="color:#cc33cc;">8n - 13 = 11</span><br /><span style="color:#cc33cc;">8n = 11 + 13 = 24</span><br /><span style="color:#cc33cc;">8n = 24</span><br /><span style="color:#cc33cc;">n = 24/8 = 3</span><br /><span style="color:#cc33cc;">n = 3 </span><br /><span style="color:#ff6600;"></span><br /><span style="color:#ff6600;">c) (8-3)n + 7n + 8 = 4n + 40</span><br /><span style="color:#ff6600;"></span><span style="color:#cc33cc;">5n + 7n + 8 = 4n + 40</span><br /><span style="color:#cc33cc;">5n + 7n - 4n = 40 - 8</span><br /><span style="color:#cc33cc;">8n = 32</span><br /><span style="color:#cc33cc;">n = 32/8 = 4</span><br /><span style="color:#cc33cc;">n = 4 </span><br /><br /><span style="color:#3333ff;">Question 5. For this question you need to create a T-chart and a graph to plot your data from this question onto.</span><br /><span style="color:#ff0000;">You are having a race against your friend, except you are on foot and he is on his bike. You both know that if you are on bike you will be faster so your friend gives you a head start of 3 minutes. If you can run <span style="color:#ff6600;">400m per minute</span>, and your friend can bike <span style="color:#ff6600;">700m per minute</span>, who will be the first one to make it to the finish line <span style="color:#ff6600;">2000m</span> away? <a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%206.jpg"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%206.jpg" border="0" /></a></span><br /><span style="color:#ff0000;"></span><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%205.jpg"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%205.jpg" border="0" /></a><br /><br /><br /><p><span style="color:#ff6600;"></span></p><p><span style="color:#ff6600;"></span></p><p><span style="color:#ff6600;"></span></p><p><span style="color:#ff6600;"></span></p><p><span style="color:#ff6600;"></span></p><p></p><p></p><p><span style="color:#cc33cc;"><a href="http://photos1.blogger.com/blogger/1619/2126/1600/untitled%201.jpg"></a></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span></p><p><span style="color:#cc33cc;"></span> </p><p><span style="color:#cc33cc;"></span> </p><p><span style="color:#cc33cc;"></span> </p><p><span style="color:#cc33cc;"></span> </p><p><span style="color:#cc33cc;"></span> </p><p><span style="color:#cc33cc;"></span> </p><p><span style="color:#cc33cc;"><a href="http://photos1.blogger.com/blogger/1619/2126/1600/untitled%201.0.jpg"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/untitled%201.0.jpg" border="0" /></a></span></p><p><span style="color:#cc33cc;"></span> </p><p><span style="color:#cc33cc;"> The runner will come in first in 5 minutes and the biker will come in second in about 6 minutes.</span></p>Smiiliieshttp://www.blogger.com/profile/04196539918571169884noreply@blogger.com6tag:blogger.com,1999:blog-20385105.post-1148871306244946012006-05-28T19:22:00.000-07:002006-05-29T06:05:32.316-07:00Janna's Growing Post for May 29th 2006<strong><span style="color:#330099;">Question 1:</span></strong> What is the difference between an algerbraic expression and an equation (Hint: One contains this and the other doesn't)? Give an example of both an expression and an equation.<br /><br />An <span style="color:#ff0000;"><strong>algebraic expression</strong></span> is when you combine <span style="color:#33cc00;">numbers,</span> <span style="color:#3333ff;">operatives,</span> <span style="color:#ff99ff;">grouping symbols</span> (such as brackets and parentheses) and/or<span style="color:#993399;"> free variables</span> and<span style="color:#ff6600;"> bound variables. </span><span style="color:#000000;">You get to choose the variable in an </span><span style="color:#ff0000;"><strong>algebraic expression.</strong></span> An example of an <span style="color:#ff0000;"><strong>algebraic expression</strong></span> is 20J / 5. In an <span style="color:#3333ff;"><strong>algebraic equation</strong> <span style="color:#000000;">is when you combine</span> <span style="color:#33cc00;">numbers,</span><strong> </strong>operatives,<span style="color:#ff99ff;"><strong> grouping symbols </strong></span><span style="color:#000000;">(such as brakets and parentheses)</span><strong> </strong><span style="color:#000000;">and/or</span><strong> </strong><span style="color:#cc66cc;">free variables</span> <span style="color:#000000;">and</span><strong> </strong><span style="color:#ff6600;">bouund variables.</span></span> In an equation the value of the variable is given. A example for an <strong><span style="color:#3333ff;">algebraic equation</span></strong> is 20J / 5 = 20. J equals 5.<br /><br /><span style="color:#000099;"><strong>Question 2:</strong></span> What is a variable and why do we use one in algebra?<br /><br />A <span style="color:#ff6600;"><strong>variable</strong></span> is a letter that replaces a number we are solving for. The variable stands for the <span style="color:#ff0000;"><strong>unknown.</strong> <span style="color:#000000;">We use a <strong><span style="color:#ff9900;">variable</span></strong> (a letter) in algebra so the equations we are solving do not become confusing. Example is we use numbers as <strong><span style="color:#ff6600;">variables</span></strong> instead of letters.</span></span><br />21 + 13 = 17 This equation doesn't make sense. Now here's the same equation except we use letters for the variable. 2A + 13 = 17. A eaquals 2. You multiply 2 by A which is 2. 2 x 2= 4. Your final equation would be 4 + 13 = 17.<br /><br /><span style="color:#3333ff;"><strong>Question 3:</strong></span> Solve for N.<br /><br /><a href="http://photos1.blogger.com/blogger/5982/2100/1600/untitled.4.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/5982/2100/320/untitled.4.jpg" border="0" /></a><br /><br />I found that since 2 circles equals 1 square and a circle equals one, that a square equals 2. To solve the second question you need to figure out what a triangle equals on the first scale. I took away four circles (each square equals two circles), and it left me with five circles. Since there were five circles left the triangle equals five circles each. Then I needed to solve the N's. If each square equals 2 and each triangle equals f circles each which is 10. I added it up and got 22. that means you now have to divide 22 in half and you'd get 11. So N eqauls 11.<br /><br /><strong><span style="color:#33ccff;">Question 4:</span></strong> Solve the following equations. Show all of the steps that are needed.<br /><br />a.) 3n+4n+7=2n+12<br /> 7n+7=2n+127n-2n(+7-7)=2n-2n(+12-7)<br /> 5n=5<br /> N=1<br /><br />b) 8n-(4+9)=1<br /> 1 8(3)-(4+9)=<br /> 1124-13=11<br /> N= 3<br /><br />(c) (8-3)n+7n+8=<br />4n+405n+7n+8=<br />4n+405(4)+7(4)+8=<br />4(4)+4020+28+8=56<br />N= 4<br /><br /><strong><span style="color:#66ffff;">Question 5:</span></strong> For this question you need to create a T-Chart and a graph to plot your data from this question onto.<br /><br /><a href="http://photos1.blogger.com/blogger/4036/2106/1600/runner%20t-chart.0.jpg"></a><a href="http://photos1.blogger.com/blogger/4036/2106/1600/biker%20t-chart.1.jpg"></a>You are having a race against your friend, except you are on foot and he is on his bike. Your both know that if you are on a bike you will be faster so your friend gives you a head start of 3 minutes. If you can run 400m per minute, and your friend can bike 700m per minute, who will be the first to make it to the finish line 2000m away?The runner will cross the finish line first in 5 minutes. The biker will cross the finish line second in 6 minutes.<a href="http://photos1.blogger.com/blogger/4036/2106/1600/Graph.0.jpg"></a>Janna_09noreply@blogger.com4tag:blogger.com,1999:blog-20385105.post-1148869062296776382006-05-28T19:17:00.000-07:002006-05-29T18:18:48.970-07:00My Growing Post<span style="color:#3333ff;">1. In an algebraic expression you get to choose the value of the variable.<br />In an algebraic equation the value of the variable is given. </span><br /><span style="color:#3333ff;"></span><br /><span style="color:#3333ff;">2.A variable is a letter that replaces a number. We use a variable in algebra because algebra is about solving the uknown and the variable is the unknown thing we have to solve.</span><br /><span style="color:#3333ff;"></span><br /><span style="color:#3333ff;">3.</span><br /><span style="color:#3333ff;"></span><a href="http://photos1.blogger.com/blogger/4117/2103/1600/shape%20graph.2.jpg"></a><a href="http://photos1.blogger.com/blogger/4117/2103/1600/shape%20graph.2.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4117/2103/320/shape%20graph.2.jpg" border="0" /></a><br /><span style="color:#3333ff;">To solve the second question you need to figure out what a triangle equals on the first scale. First I took away four circles (each square equals two circles), and it left me with five circles. Since there were five circles left the triangle equals five circles. To solve the second question you need to figure out the value of the two Ns. First I added the squares and triangles together. The total of the squares and triangles and it was 22 circles. Then I divided the 22 circles by 2. The answer was 11. So each N equals 11 circles. </span><br /><span style="color:#3333ff;"></span><br /><span style="color:#3333ff;">4. .(a) 3n+4n+7= </span><span style="color:#3333ff;"><br />2n+123(1)+4(1)+7=<br />2(1)+123+4+7=14<br />N= 1</span><br /><span style="color:#3333ff;"><br /></span><span style="color:#3333ff;">b) 8n-(4+9)=1<br />1 8(3)-(4+9)=<br />1124-13=<br />11N= 3<br /><br />(c) (8-3)n+7n+8=<br />4n+405n+7n+8=<br />4n+405(4)+7(4)+8=<br />4(4)+4020+28+8=56<br />N= 4<br /><br />5.</span><span style="color:#3333ff;"><br /></span><br /><span style="color:#3333ff;"><a href="http://photos1.blogger.com/blogger/4117/2103/1600/BIKER.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4117/2103/320/BIKER.jpg" border="0" /></a><a href="http://photos1.blogger.com/blogger/4117/2103/1600/RUNNER.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4117/2103/320/RUNNER.jpg" border="0" /></a> <a href="http://photos1.blogger.com/blogger/4117/2103/1600/BIKER%20AND%20RUNNER%20GRAPH.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4117/2103/320/BIKER%20AND%20RUNNER%20GRAPH.jpg" border="0" /></a><br />The Runner will cross the finish line first in 5 minutes. The biker will cross the finish line second in 6 minutes.<br /><br /></span><br /><br /><br /><br /></span>Candynoreply@blogger.com4tag:blogger.com,1999:blog-20385105.post-1148863486334194362006-05-28T17:44:00.000-07:002006-05-28T17:44:46.583-07:00GROWING POSSTT !!<span style="font-family:Arial;font-size:85%;"><strong>Question 1.)</strong> <em>What is the difference between an algebraic expression and an equation (hint: One contains this and the other doesn't)? Give an example of both an expression and an equation.</em></span><br /><em><span style="font-family:Arial;font-size:85%;"></span></em><br /><span style="font-family:arial;font-size:85%;">Algebraic Expression you get to choose the value of the variable.</span><br /><span style="font-family:arial;font-size:85%;">Algebraic Equation the value of the variable is already given.</span><br /><span style="font-family:arial;"><span style="font-size:85%;"><strong>Algebraic Expression:</strong> 8A+6</span></span><br /><span style="font-family:arial;font-size:85%;"><strong>Algebraic Equation: </strong>8A+6=30</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:arial;font-size:85%;"><strong>Question 2.)</strong> <em>What is a variable and why do we use one in algebra?</em></span><br /><em><span style="font-family:Arial;font-size:85%;"></span></em><br /><span style="font-family:Arial;font-size:85%;">A variable is a letter that replaces a number. We use it in algebra beacause algebra is about finding the unknown, and the variable is the unknown thing we must solve in a problem.</span><br /><br /><span style="font-family:arial;font-size:85%;"><strong>Question 4.)</strong> <em>Solve the following equations. Show all of the steps that are needed.</em></span><br /><em></em><br /><span style="font-family:Arial;font-size:85%;"><strong>a.)</strong> 3n+4n+7=2n+12</span><br /><span style="font-family:Arial;font-size:85%;">7n+7=2n+127n-2n(+7-7)=2n-2n(+12-7)</span><br /><span style="font-family:Arial;font-size:85%;">5n=5</span><br /><span style="font-family:Arial;font-size:85%;">n=1</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;"><strong>b.)</strong> 8n-(4+9)=11</span><br /><span style="font-family:Arial;font-size:85%;">8n-13=11</span><br /><span style="font-family:Arial;font-size:85%;">+13 +13</span><br /><span style="font-family:Arial;font-size:85%;">8n=24</span><br /><span style="font-family:Arial;font-size:85%;">n=24/8</span><br /><span style="font-family:Arial;font-size:85%;">n=3</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;"><strong>c.)</strong> (8-3)n+7n+8=4n+40</span><br /><span style="font-family:Arial;font-size:85%;">5n+7n+8 =4n+40</span><br /><span style="font-family:Arial;font-size:85%;">12n+8=4n+40</span><br /><span style="font-family:Arial;font-size:85%;">12n(+8-8)=4n(+40-8)</span><br /><span style="font-family:Arial;font-size:85%;">12n-4n=(4n-4n)+32</span><br /><span style="font-family:Arial;font-size:85%;">8n=32</span><br /><span style="font-family:Arial;font-size:85%;">n=4</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;"><strong>Question 5.)</strong> </span><span style="font-family:Arial;font-size:85%;"><em>For this question you need to create a T-Chart and a graph to plot your data from this question onto.</em><a href="http://photos1.blogger.com/blogger/4036/2106/1600/runner%20t-chart.0.jpg"></a><a href="http://photos1.blogger.com/blogger/4036/2106/1600/biker%20t-chart.1.jpg"></a><a href="http://photos1.blogger.com/blogger/4036/2106/1600/Graph.0.jpg"></a></span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;">You are having a race against your friend, except you are on foot and he is on his bike. Your both know that if you are on a bike you will be faster so your friend gives you a head start of 3 minutes. If you can run 400m per minute, and your friend can bike 700m per minute, who will be the first to make it to the finish line 2000m away?</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:Arial;font-size:85%;">The runner will cross the finish line first in 5 minutes. The biker will cross the finish line second in 6 minutes.</span>bl4z3nhttp://www.blogger.com/profile/13196062698989098094noreply@blogger.com5tag:blogger.com,1999:blog-20385105.post-1148776296333832292006-05-27T17:14:00.000-07:002006-05-29T14:05:48.076-07:00My Growing Post Due Monday May 29th<span style="color:#ff0000;">Question 1: What is the difference between an algebraic expression and an equation (hint: One contains this and the other doesn't)? Give an example of both an expression and an equation.</span><br /><span style="color:#ff0000;"></span><br /><span style="color:#3366ff;">In an <span style="color:#009900;">algebraic expression</span> you get to choose the value of the variable.</span><br /><span style="color:#3366ff;">In an <span style="color:#33ffff;">algebraic equation</span> the value of the variable is given.</span><br /><span style="color:#009900;">Algebraic Expression: 9N+4</span><br /><span style="color:#33ffff;">Algebraic Equation: 9N+4=22</span><br /><span style="color:#ff0000;"><br /></span><span style="color:#ff0000;">Question 2: What is a variable and why do we use one in algebra?</span><br /><span style="color:#ff0000;"></span><br /><span style="color:#3366ff;">A <span style="color:#660000;">variable</span> is a letter that replaces a number. We use a <span style="color:#660000;">variable </span>in algebra because algebra is about solving the uknown and the <span style="color:#660000;">variable</span> is the unknown thing we have to solve.<br /></span><span style="color:#ff0000;"></span><br /><span style="color:#ff0000;">Question 3: Solve for N</span><br /><br /><a href="http://photos1.blogger.com/blogger/4036/2106/1600/solve%20for%20n.1.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4036/2106/320/solve%20for%20n.1.jpg" border="0" /></a><br /><span style="color:#3366ff;">To solve the second question, you need to figure out what a <span style="color:#99ff99;">triangle</span> equals on the first scale.</span><br /><span style="color:#3366ff;">First, I took away four <span style="color:#cc6600;">circles</span> (each <span style="color:#990000;">square</span> equals two <span style="color:#cc6600;">circles</span>), which left me with five <span style="color:#cc6600;">circles</span>. Since there were five circles left, the <span style="color:#99ff99;">triangle</span> equals five <span style="color:#cc6600;">circles</span>.</span><br /><span style="color:#3366ff;">To solve the second question, you need to figure out the value of the two Ns.</span><br /><span style="color:#3366ff;">First, I added the <span style="color:#990000;">squares</span> and <span style="color:#99ff99;">triangles</span> together. The total of the <span style="color:#990000;">squares</span> and <span style="color:#99ff99;">triangles<span style="color:#3366ff;">,</span> </span>together, was 22 <span style="color:#cc6600;">circles</span>. Then I divided the 22 <span style="color:#cc6600;">circles</span> by 2. The answer was 11. So each N equals 11 <span style="color:#cc6600;">circles</span>.</span><br /><span style="color:#3366ff;"><br /></span><span style="color:#ff0000;">Question 4: Solve the following equations. Show all of the steps that are needed. </span><br /></span><span style="color:#ff0000;"><br /></span><span style="color:#33ff33;">(a) 3n+4n+7=2n+12</span><br /><br /><span style="color:#33ff33;">7n+7=2n+12<br /></span><br /><span style="color:#33ff33;">7n-2n(+7-7)=2n-2n(+12-7)<br /></span><br /><span style="color:#33ff33;">5n=5<br /></span><br /><span style="color:#33ff33;">n=1<br /></span><br /><span style="color:#330099;">(b) 8n-(4+9)=11<br /></span><br /><span style="color:#330099;">8n-13=11<br /></span><br /><span style="color:#330099;">+13 +13<br /></span><br /><span style="color:#330099;">8n=24<br /></span><br /><span style="color:#330099;">n=24/8<br /></span><br /><span style="color:#330099;">n=3<br /></span><br /><span style="color:#ffcccc;">(c) (8-3)n+7n+8=4n+40<br /></span><br /><span style="color:#ffcccc;">5n+7n+8 =4n+40<br /></span><br /><span style="color:#ffcccc;">12n+8=4n+40<br /></span><br /><span style="color:#ffcccc;">12n(+8-8)=4n(+40-8)<br /></span><br /><span style="color:#ffcccc;">12n-4n=(4n-4n)+32<br /></span><br /><span style="color:#ffcccc;">8n=32<br /></span><br /><span style="color:#ffcccc;">n=4</span><br /><br /><span style="color:#ff0000;">Question 5: For this question you need to create a T-Chart and a graph to plot your data from this question onto.<br /></span><br /></span><a href="http://photos1.blogger.com/blogger/4036/2106/1600/runner%20t-chart.0.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4036/2106/320/runner%20t-chart.0.jpg" border="0" /></a> <a href="http://photos1.blogger.com/blogger/4036/2106/1600/biker%20t-chart.1.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4036/2106/320/biker%20t-chart.1.jpg" border="0" /></a><br /><br /><a href="http://photos1.blogger.com/blogger/4036/2106/1600/Graph.0.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/4036/2106/320/Graph.0.jpg" border="0" /></a><br /><br /><br /><br /><span style="color:#ff0000;">You are having a race against your friend, except you are on foot and he is on his bike. Your both know that if you are on a bike you will be faster so your friend gives you a head start of 3 minutes. If you can run 400m per minute, and your friend can bike 700m per minute, who will be the first to make it to the finish line 2000m away?</span><br /><br /><span style="color:#3366ff;">The runner will cross the finish line first in 5 minutes. The biker will cross the finish line second in 6 minutes.</span><br /><span style="color:#3366ff;"></span><br /><span style="color:#3366ff;"></span><br /><span style="color:#ffcc99;">Kendra Valentonis 7-43</span>Fang_the_Barbarianhttp://www.blogger.com/profile/07926464780699354515noreply@blogger.com9tag:blogger.com,1999:blog-20385105.post-1148492902423549112006-05-24T10:48:00.000-07:002006-05-25T10:25:40.980-07:00Janna's Growing Post<span style="font-weight: bold;">Quetsion #1: Solve all 3 parts of the problem below.</span><br /><br /><span style="font-weight: bold;">Jack collects baseball cards. Jack has 180 baseball cards in his collection. At the end of each month jack buys 25 baseball cards to add to his collection.</span><br /><br /><span style="font-weight: bold;">A)</span><br /><a style="font-weight: bold;" onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/5982/2100/1600/blog%20thinger.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/5982/2100/320/blog%20thinger.jpg" alt="" border="0" /></a><br /><span style="font-weight: bold;">B) 180 + 25( j ) = 280</span><br /><br /><span style="font-weight: bold;">C) Jack will have 1380 when he turns 12.</span><br /><br /><span style="font-weight: bold;">Question #2:</span><br /><br /><span style="font-weight: bold;">A) Jackie should order 2 pizzas . Because if each peron eats 3 pieces of pizza and there are 6 slices in a pizza. That means 2 people can finish 1 pizza. Since there are 4 people, that means they can finish 2 pizzas.</span><br /><br /><span style="font-weight: bold;">B) Jackie needs to order one more pizza. Because 2 people can finish 1 pizza.</span><br /><br /><span style="font-weight: bold;">Questions #3:</span><br /><br /><span style="font-weight: bold;">A) </span><span style="color: rgb(51, 51, 153); font-weight: bold;"><span style="color: rgb(0, 0, 0);">Cathy will have $200.00 dollars in her saving account. I got the answer by using her formula of <span style="color: rgb(255, 0, 0);">20+15(12).</span> The first thing i did was I mulitplied 12 by 15 to get 180 then i added her $20.00 dollars to get $200.00 dollars in total.<br /><br />B) </span></span><span style="font-weight: bold;">If Cathy made a mistake and she had actually had $25.00 dollars instead of $20.00 the formula would now be:</span><br /><br /><span style="font-weight: bold;">25 + 15A = savings account</span><br /><span style="font-weight: bold;">Then Cathy would have a total of $205.00 dollars for that 1 year</span><br /><br /><strong>Question #4: </strong><span style="font-weight: bold;"></span><br /><br /><span style="font-weight: bold; color: rgb(0, 0, 0);">a) 3n + 4n + 7 = 2n + 12</span><br /><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">3n+4n+7=2n+12</span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">3(1)+4(1)+7=2(1)+12</span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">3+4+7=14</span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /><span style="color: rgb(102, 102, 0);"><span style="color: rgb(0, 0, 0); font-weight: bold;">N= 1</span><br /></span><br /><br /><span style="font-weight: bold; color: rgb(0, 0, 0);">b) 8n – (4 + 9) = 11</span><br /><p style="font-weight: bold; color: rgb(0, 0, 0);">8n-(4+9)=11</p><p style="font-weight: bold; color: rgb(0, 0, 0);">8(3)-(4+9)=11</p><p style="font-weight: bold; color: rgb(0, 0, 0);">24-13=11</p><p><span style="color: rgb(0, 0, 0); font-weight: bold;">N= 3</span></p><p><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /></p><span style="font-weight: bold;">c) (8 – 3 )n + 7n + 8 = 4n + 40</span><br /><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">(8-3)n+7n+8=4n+40</span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">5n+7n+8=4n+40</span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">5(4)+7(4)+8=4(4)+40</span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">20+28+8=56</span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;"></span><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">N= 4</span>Janna_09noreply@blogger.com5tag:blogger.com,1999:blog-20385105.post-1148436293609380392006-05-23T19:04:00.000-07:002006-05-24T19:49:00.670-07:00Growing Post<span style="font-size:+0;"><span style="COLOR: rgb(102,204,204)">Question 1:</span><br /><br /><span style="COLOR: rgb(102,204,204)">A) </span><span style="COLOR: rgb(102,204,204); FONT-STYLE: italic">Create a T-Chart showing how many baseball cards Jack has at the end of the next 4 months.</span><br /><br /></span><span style="font-size:+0;"></span><div style="COLOR: rgb(102,204,204); TEXT-ALIGN: center"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/1831/2100/1600/GrowingPost4.jpg"><span style="font-size:+0;"><img style="CURSOR: pointer" alt="" src="http://photos1.blogger.com/blogger/1831/2100/320/GrowingPost4.jpg" border="0" /></span></a><span style="font-size:+0;"><br /></span></div><br /><br /><span style="font-size:+0;"><span style="COLOR: rgb(102,204,204)">B)</span><span style="COLOR: rgb(102,204,204); FONT-STYLE: italic"> Create an algebraic formula based upon the problem above. </span><br /><span style="COLOR: rgb(102,204,204)">180 + 25T = Amount of baseball cards</span><br /><span style="COLOR: rgb(102,204,204)">T = The Month(s)</span><br /><br /><span style="COLOR: rgb(102,204,204)">C) </span><span style="COLOR: rgb(102,204,204); FONT-STYLE: italic">If Jack just turned 8 years old this month and Jack continues to buy the same amount of baseball cards each month, how many baseball cards will jack have when he turns 12?</span><br /><span style="COLOR: rgb(102,204,204)">Jack will have </span><span style="FONT-WEIGHT: bold; COLOR: rgb(102,204,204)">1380 </span><span style="COLOR: rgb(102,204,204)">card by the time he's twelve.</span><br /><span style="FONT-WEIGHT: bold; COLOR: rgb(102,204,204)">Forty-eight months</span><span style="COLOR: rgb(102,204,204)"> until Jack is twelve. </span><span style="FONT-WEIGHT: bold; COLOR: rgb(102,204,204)">48 X 25 = 1200</span><br /><span style="COLOR: rgb(102,204,204)">But add the cards he already has; one hundred eighty.</span><br /><span style="FONT-WEIGHT: bold; COLOR: rgb(102,204,204)">1200 + 180= 1380</span> </span><br /><p><span style="font-size:+0;color:#66cccc;">Formula: 180 + 25T= 1380</span></p><p><span style="color:#66cccc;">(T = 48)</span><span style="font-size:+0;"></p><br /><br /><span style="COLOR: rgb(255,0,0)">Question 2:</span><br /><br /><br /></span><div style="COLOR: rgb(102,204,204); TEXT-ALIGN: center"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/1831/2100/1600/GraphGrowingPost.gif"><span style="font-size:+0;"><img style="WIDTH: 356px; CURSOR: pointer; HEIGHT: 252px" alt="" src="http://photos1.blogger.com/blogger/1831/2100/320/GraphGrowingPost.png" border="0" /></span></a></div><span style="font-size:+0;"><span style="COLOR: rgb(255,0,0)">A)</span><span style="COLOR: rgb(255,0,0); FONT-STYLE: italic"> If Jackie thinks that there will be four people at the party (counting herself) how many pizza’s should she order?</span><br /><span style="COLOR: rgb(255,0,0)">If Jackie has three friends she will need to have at least two pizzas so she can supply herself.</span><br /><span style="COLOR: rgb(255,0,0)">12 slices = 2 pizzas</span><br /><span style="COLOR: rgb(255,0,0)">12 slices = 4 people</span> <br /><br /><span style="COLOR: rgb(255,0,0)">B) </span><span style="COLOR: rgb(255,0,0); FONT-STYLE: italic">If two more people show up at the party how many more pizza’s does she need to order?</span><br /><span style="COLOR: rgb(255,0,0)">If more people show up she will have to order </span><span style="FONT-WEIGHT: bold; COLOR: rgb(255,0,0)">three pizzas</span><span style="COLOR: rgb(255,0,0)">, since </span><span style="FONT-WEIGHT: bold; COLOR: rgb(255,0,0)">one pizza</span><span style="COLOR: rgb(255,0,0)"> </span><span style="FONT-WEIGHT: bold; COLOR: rgb(255,0,0)">supports two people.</span><br /><br /><span style="COLOR: rgb(255,204,102)">Question 3:</span><br /><br /><br /><span style="COLOR: rgb(255,204,102)">A) </span><span style="COLOR: rgb(255,204,102); FONT-STYLE: italic">Calculate how much money Kathy will have in one year</span><span style="COLOR: rgb(255,204,102)">.</span><br /><span style="COLOR: rgb(255,204,102)">First multiply the months by the amount of money she recieves; </span><span style="FONT-WEIGHT: bold; COLOR: rgb(255,204,102)">15 X 12 = 180</span><br /><span style="COLOR: rgb(255,204,102)">Add 20 to the sum; </span><span style="FONT-WEIGHT: bold; COLOR: rgb(255,204,102)">200 + 20 = 200 </span><br /><br /><br /></span><span style="font-size:+0;"></span><div style="COLOR: rgb(255,204,102); TEXT-ALIGN: center"><div style="TEXT-ALIGN: left"><span style="font-size:+0;">B) <span style="FONT-STYLE: italic">Calculate how much money Kathy will have in one year.</span><br />This answer is quite simple. All you do is change the 20 in Kathy's formula, and change it to 25.<br /></span></div><span style="font-size:+0;"><span style="FONT-WEIGHT: bold">25 + 15n = Savings</span><br /></span></div><span style="font-size:+0;"><span style="COLOR: rgb(255,204,102)">If that was what Kathy had in her account, then her savings would be </span><span style="FONT-WEIGHT: bold; COLOR: rgb(255,204,102)">$205</span><span style="COLOR: rgb(255,204,102)">.</span><br /><br /><span style="COLOR: rgb(51,204,0)">Question Four:</span><br /><br /><span style="COLOR: rgb(51,204,0)">A) </span><span style="COLOR: rgb(51,204,0); FONT-STYLE: italic">3N + 4N + 7 = 12 + 2N</span><br /><span style="COLOR: rgb(51,204,0)">3(1) + 4(1) + 7 = 2(1) = 12</span><br /><span style="COLOR: rgb(51,204,0)">3 + 4 + 7 = 14</span><br /><span style="FONT-WEIGHT: bold; COLOR: rgb(51,204,0)">N = 1</span><br /><br /><span style="COLOR: rgb(51,204,0)">B) </span><span style="COLOR: rgb(51,204,0); FONT-STYLE: italic">8N - ( 4 + 9) = 11</span><br /><span style="COLOR: rgb(51,204,0)">8N - (4 + 9) = 11</span><br /><span style="COLOR: rgb(51,204,0)">8(3) - (4 + 9) = 11</span><br /><span style="COLOR: rgb(51,204,0)">24 - 13 = 11</span><br /><span style="FONT-WEIGHT: bold; COLOR: rgb(51,204,0)">N = 3</span><br /><br /><span style="COLOR: rgb(51,204,0)">C) </span><span style="COLOR: rgb(51,204,0); FONT-STYLE: italic">(8 - 3)N + 7N + 8 = 4N + 40</span><br /><span style="COLOR: rgb(51,204,0)">5N + 7N + 8 = 4N + 40</span><br /><span style="COLOR: rgb(51,204,0)">5(4) + 7(4) + 8 = 4(4) + 40</span><br /><span style="COLOR: rgb(51,204,0)">20 + 28 + 8 = 56</span><br /><span style="FONT-WEIGHT: bold; COLOR: rgb(51,204,0)">N = 4</span></span>Ariahttp://www.blogger.com/profile/12976271291206028698noreply@blogger.com7tag:blogger.com,1999:blog-20385105.post-1148426870081280402006-05-23T16:10:00.000-07:002006-06-19T15:02:01.093-07:00THE GROWING POST!!!!!!!!!!!!!!!!!!!!!!<strong><span style="color: rgb(255, 0, 0);">Mark you received 15/17 for this post</span><br /><br />Jack collects baseball cards. Jack has 180 baseball cards in his collection. At the end of each month Jack buys 25 baseball cards to add to his collection.<br /><br />a) Create a T-Chart showing how many baseball cards Jack has at the end of the next 4 months.<br /></strong><a href="http://photos1.blogger.com/blogger/564/2108/1600/232.0.jpg"><img style="" alt="" src="http://photos1.blogger.com/blogger/564/2108/400/232.0.jpg" border="0" /></a><br /><br /><strong>b) Create an algebraic formula based upon the problem above</strong><br />180 + 25(4) = 280<br /><br /><strong>c) If Jack just turned 8 years old this month and Jack continues to buy the same amount of baseball cards each month, how many baseball cards will jack have when he turns 12?</strong><br /><br />Jack is going to have 1380 baseball cards when he turns 12.<br /><br /><strong>Question #2: Use the chart to figure out the questions below.</strong><br /><br /><strong><em>Jackie is planning on having a pizza party with some of her friends. She is trying to figure out how many pizzas she has to order. She knows that each pizza has six slices of pizza.</em></strong><br /><br />A)If there is four people coming to the party then she will need 2 pizzas all together. Which count as 12 slices.<br /><br />If the two people come and show up at the party then Jackie should order one more pizza to make three pizzas. Jackie should order 3 pizzas because look at the chart, and you will find 6 people and altogether will have 18 slices. Then you will divide and get the answer of 3 pizzas in total.<br /><br /><strong>Question #3: Answer the questions below based upon this informationKathy has $20 in her savings account. Each month she adds another $15 to her savings account. In order to calculate how much money she will have in one year Kathy has created this algebraic formula: 20 + 15n = Savings amount<br />a) Calculate how much money Kathy will have in one year</strong><br />Kathy is going to have $200.00 in total.<br /><strong>b) Suppose Kathy counted wrong and she really has $25 in her account instead of $20. Change the algebraic formula to reflect this miscalculation.<br /></strong>If she could of made a mistake of having $25.00 then the formula would be 25+15n= savings she would then have $205.00 dollars.<br /><br /><strong>Question #4: Solve the following equations. Show all of the steps that are needed.<br /></strong>A) 3n + 4n + 7 = 2n + 12 3n+4n+7=2n+12 3(1) +4(1) +7=2(1) +12 3+4+7=14<br />N= 1<br />B) 8n – (4 + 9) = 11 8n-(4+9) =11 8(3)-(4+9) =11 24-13=11<br />N= 3<br />C) (8 – 3) n + 7n + 8 = 4n + 40 (8-3) n+7n+8=4n+40 5n+7n+8=4n+40 5(4) +7(4) +8=4(4) +40<br />20+28+8=56<br />N= 4BeanShttp://www.blogger.com/profile/00387291691605327582noreply@blogger.com0tag:blogger.com,1999:blog-20385105.post-1148426894563495802006-05-23T15:56:00.000-07:002006-05-24T05:46:01.756-07:00My Growing Post Due Tuesday May 23rd<span style="color: rgb(51, 51, 255);">1.</span> <span style="color: rgb(51, 51, 255);">(a) Jack will have the total of 280 baseball cards at the end of the next 4 months</span><br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/4036/2106/1600/tchart.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/4036/2106/320/tchart.jpg" alt="" border="0" /></a><br /><span style="color: rgb(51, 51, 255);">(b) 180+</span><span style="color: rgb(51, 51, 255);">25(C)= #of cards 180+25(4)=280 cards</span><br /><span style="color: rgb(51, 51, 255);">First I started off multiplying the number of months, and that is 4, by 25, the number of cards he buys after each</span><span style="color: rgb(51, 51, 255);"> month. I then added his remaining 180 cards to get the total. Then he will have 280 cards at the end of the next 4 months.<br /><br /></span><span style="color: rgb(51, 51, 255);">(c) </span><span style="color: rgb(51, 51, 255);">Jack will have the total of 1</span><span style="color: rgb(51, 51, 255);">380 cards when he turns 12.</span><br /><span style="color: rgb(51, 51, 255);">I got the answer by finding the difference between 8 and 12, and that is 4. I multiplied 4 by 12 and I got 48 because there are 48 months in 4 years. I then used the algebraic formula, 180+25(48). All that I did was cha</span><span style="color: rgb(51, 51, 255);">nge the variable. Then I multiplied 48 by 25 to give me 1200, and then I added the remaining 180 to get 1380 cards.</span><br /><span style="color: rgb(51, 51, 255);"><br /><br />2. </span><span style="color: rgb(51, 51, 255);">(a) Jackie should order the total of 2 whole pizzas. She should order 2 pizzas because if you look at th</span><span style="color: rgb(51, 51, 255);">e chart and find 4 people there will be 12 slices and if there are 6 slices in each pizza. I divide 12 by 6 and that gave me 2 whole pizzas.<br /></span><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/4036/2106/1600/pizza%20chart.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/4036/2106/320/pizza%20chart.jpg" alt="" border="0" /></a><br /><span style="color: rgb(51, 51, 255);">(b) If two more people show up at the party, Jackie would have to order 1 more pizza, making the total 3 pizzas. She should order 3 pizzas in total becuase if you look at the chart and find 6 people there will be 18 slices. Divide 18 slices by 6 to get the total of 3 pizzas.<br /><br /></span><span style="color: rgb(51, 51, 255);">3. (a) Cathy will have $200.00 dollars in her saving account. I got the answer by taking the algebraic formula of 20+15(12). I then mulitplied 12 by 15 to get 180. I then added her $20.00 dollars to get $200.00 dollars.<br /></span><span style="color: rgb(51, 51, 255);">(b) If Cathy made a mistake and she had actually had $25.00 dollars instead of $20.00, the algebraic formula would be 25+15N= savings account total. Cathy then would have a total of $205.00 dollars for that year.<br /><br /></span><p><span style="color: rgb(51, 51, 255);">4. (a) 3n+4n+7=2n+12</span></p><p><span style="color: rgb(51, 51, 255);">7n+7=2n+12</span></p><p><span style="color: rgb(51, 51, 255);">7n-2n(+7-7)=2n-2n(+12-7)</span></p><p><span style="color: rgb(51, 51, 255);">5n=5</span></p><p><span style="color: rgb(51, 51, 255);">n=1 <br /></span></p><p><span style="color: rgb(51, 51, 255);">(b) 8n-(4+9)=11</span></p><p><span style="color: rgb(51, 51, 255);"> </span><span style="color: rgb(51, 51, 255);">8n-13=11</span></p><p><span style="color: rgb(51, 51, 255);"> +13 +13</span></p><p><span style="color: rgb(51, 51, 255);">8n=24</span></p><p><span style="color: rgb(51, 51, 255);">n=24/8</span></p><p><span style="color: rgb(51, 51, 255);">n=3<br /></span></p><p><span style="color: rgb(51, 51, 255);">(c) (8-3)n+7n+8=4n+40</span></p><p><span style="color: rgb(51, 51, 255);">5n+7n+8 =4n+40</span></p><p><span style="color: rgb(51, 51, 255);">12n+8=4n+40</span></p><p><span style="color: rgb(51, 51, 255);">12n(+8-8)=4n(+40-8)</span></p><p><span style="color: rgb(51, 51, 255);"> 12n-4n=(4n-4n)+32</span></p><p><span style="color: rgb(51, 51, 255);">8n=32</span></p><p><span style="color: rgb(51, 51, 255);">n=4<br /></span></p><br /><span style="color: rgb(51, 51, 255);"> </span>Fang_the_Barbarianhttp://www.blogger.com/profile/07926464780699354515noreply@blogger.com6tag:blogger.com,1999:blog-20385105.post-1148428926625893522006-05-23T15:29:00.000-07:002006-05-28T10:06:37.166-07:00Kim's Growing Post<span style="color:#ffcccc;"><br />Question #1: solve all 3 parts of the problem below<br /></span><br /><span style="color:#009900;">Jack collects baseball cards. Jack has 180 baseball cards in his collection. At the end of each month Jack bys 25 baseball cards to add to his collection.<br /><br /></span><span style="color:#ff99ff;">a) Create a T-chart showing how many basball cards Jack has at the end of the next 4 months. </span><a href="http://photos1.blogger.com/blogger/1619/2126/1600/math%202.0.jpg"><span style="color:#ff99ff;"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/math%202.0.jpg" border="0" /></span></a><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><span style="color:#ff99ff;">b) Create an algebraic formula based upon the probelm above </span><br /><span style="color:#993399;">180 + 25 (n) = the number of cards</span><br /><span style="color:#993399;">n = the month</span><br /><br /><span style="color:#cc66cc;">c) If Jack just turned 8 years old this month and Jack continues to buy the same amount of baseball cards each month, how many baseball cards will Jack have when he turns 12? </span><br /><span style="color:#993399;">If you use the algebraic formula, all you have to do is: 180 + 25 (n) = the number of cards. In this case, the answer would be 1380 because you take 12 - 8 = 4. Then you take 4 (which are the years he has until he turns 12) and you times it by 12 (which is the total months in a year) and you will get 48, then if you use 48 as the variation (n), and you do the algebraic formula, you will get 1380 as your answer.</span><br /><span style="color:#993399;"></span><br /><span style="color:#ffcccc;">Question #2: Use the chart to figure out the questions below.</span><br /><br /><a href="http://photos1.blogger.com/blogger/1619/2126/1600/pic.jpg"><img style="FLOAT: left; MARGIN: 0px 10px 10px 0px; CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1619/2126/320/pic.jpg" border="0" /></a><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><span style="color:#009900;">Jackie is planning on having a pizza party with some of her friends. She is trying to figure out how many pizza's to order. She knows that each pizza has six slices of pizza.</span><br /><span style="color:#009900;"></span><br /><span style="color:#ff99ff;">a) If Jackie thinks that htere will be four people at the party (counting herself) how many pizza's should she order?</span><br /><span style="color:#993399;">Jackie should order 2 pizza's because there are a total of 4 people (counting Jackie) and each person eats 3 slices and each pizza contains 6 slices </span><span style="color:#ffcc00;">and if you look at the chart above, you will see that 4 people need 12 slices and 12 slices means 2 pizzas in total. (this is the correction that I have made, the colour yellow)</span><br /></span><span style="color:#ff99ff;">b) If two more people show up at the party how many more pizza's does she need to order</span><span style="color:#cc33cc;">?</span><br /><span style="color:#cc33cc;">Jackie needs to order 3 pizza's in total because every 2 people eat up a total of 1 pizza so if there are 6 people, 6 divided by 2 is 3, Jackie will need to order 3 pizza's for her party.</span><br /><span style="color:#cc33cc;"></span><br /><span style="color:#ffcccc;">Question #3: Answer the questions below based upon this information.</span><br /><span style="color:#ffcccc;"></span><br /><span style="color:#33cc00;">Kathy has $20 in her savings account. Each month she adds another $15 to her savings acount. In order to caculate how much money she will have in one year Kathy has created this algebraic formula: 20 + 15n = Savings amount.</span><br /><span style="color:#33cc00;"></span><br /><span style="color:#ff99ff;">a) Caculate how much money Kathy will have in one year.</span><br /><span style="color:#ff99ff;"></span><span style="color:#cc33cc;">I got the answer of $200 which is the money that Kathy will have in one year. I got that answer by using Kathy's formula which is 20 + 15n (n = 12). I multiplied 15 by 12 (which are the months in a year) and I got 180. After that, I added 20 to 180 and got $200. </span><br /><span style="color:#cc33cc;"></span><br /><span style="color:#ff99ff;">b) Suppose Kathy counted wrong and she really has $25 in her account instead of $20. Change the algebraic formula to reflect this miscaculation.</span><br /><span style="color:#ff99ff;"></span><span style="color:#cc33cc;">If Kathy did counted wrong and she had $25 in her account then all you have to do is change the number 20 to 25 and for example, it will be like this: 25 + 15n = savings amount. So Kathy will have a total of $205 if she made the miscaculation.</span><br /><span style="color:#cc33cc;"></span><br /><span style="color:#ffcccc;">Question #4: solve the following equations. Show all of the steps that are needed.</span> ( we did not need to do these questions, so I do not have them)<br /><span style="color:#ffcccc;"></span><br /><br /><span style="color:#cc33cc;">Kim Thanh Vo 7-43</span>Smiiliieshttp://www.blogger.com/profile/04196539918571169884noreply@blogger.com8tag:blogger.com,1999:blog-20385105.post-1148318542422638542006-05-22T09:36:00.000-07:002006-05-22T10:22:23.826-07:00My Growing PostQuestion#1<br /><br />A<br /><a href="http://photos1.blogger.com/blogger/6479/2100/1600/t.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/6479/2100/320/t.jpg" border="0" /></a><a href="http://photos1.blogger.com/blogger/6479/2100/1600/E.jpg"></a><br />B A=months Ax25= answer<br /><br />C She would have 900 cards<br /><br />Question#2<br /><a href="http://photos1.blogger.com/blogger/6479/2100/1600/E.jpg"></a><br /><a href="http://photos1.blogger.com/blogger/6479/2100/1600/E.jpg"></a><a href="http://photos1.blogger.com/blogger/6479/2100/1600/E.0.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/6479/2100/320/E.0.jpg" border="0" /></a><br />A She should order 2 pizza<br /><br />B She should order 1 more pizza<br /><br />Question#3<br /><br />A She will have $200<br /><br />B 25+15n<br /><br /><a href="http://photos1.blogger.com/blogger/6479/2100/1600/E.jpg"></a><a href="http://photos1.blogger.com/blogger/6479/2100/1600/t.jpg"></a>Levonhttp://www.blogger.com/profile/12404787788426329485noreply@blogger.com5tag:blogger.com,1999:blog-20385105.post-1148312555633910752006-05-22T07:33:00.000-07:002006-05-22T08:50:25.636-07:00My Growing Post<span style="color:#3333ff;">1.(a) Jack will have the total of 280 cards at the end of the next 4 months. <a href="http://photos1.blogger.com/blogger/4117/2103/1600/tchart.3.jpg"><img style="WIDTH: 232px; CURSOR: hand; HEIGHT: 157px" height="153" alt="" src="http://photos1.blogger.com/blogger/4117/2103/320/tchart.3.jpg" width="320" border="0" /></a></span><br /><span style="color:#3333ff;">(b) 180+25(C)= #of cards 180+25(4)=280 cards</span><br /><span style="color:#3333ff;">First I started off by multiplying the number of months, and is 4 by 25 the number of cards he buys after each month. Then I added his remaing 180 cards to get the total. Then he will have 280 cards at the end of the next 4 months. </span><br /><br /><span style="color:#3333ff;">(c) </span><span style="color:#3333ff;">Jack will have the total of 1380 cards when he turns 12.</span><br /><span style="color:#3333ff;">I got the answer by finding out the difference between 8 and 12, and it's 4. I multiplied 4 by 12 and I got 48 because there are 48 months in 4 years. Then I used the algebraic formula, 180+25(48). All that I did was change the variable. Then I multiplied 48 by 25 to give me 1200, and then I added the remaining 180 to get 1380 cards.</span><span style="color:#3333ff;"> </span><br /><span style="color:#3333ff;"></span><br /><span style="color:#3333ff;">2.(a) Jackie should order the total of 2 pizzas. She should order 2 pizzas because if you look at the chart and find 4 people there will be 12 slices and if there are 6 slices in each pizza I divide 12 by 6 and that gave me 2 whole pizzas.<br /><br /></span><span style="color:#3333ff;"></span><p><span style="color:#3333ff;"><a href="http://photos1.blogger.com/blogger/4117/2103/1600/pizza.jpg"><img style="WIDTH: 338px; CURSOR: hand; HEIGHT: 226px" height="206" alt="" src="http://photos1.blogger.com/blogger/4117/2103/320/pizza.jpg" width="321" border="0" /></a></span></p><p><span style="color:#3333ff;">(b) If two more people show up at the party Jackie should order 1 more pizza making the total of 3 pizzas. She should order 3 pizzas in total becuase if you look at the chart and find 6 people there will be 18 slices. I divided 18 slices by 6 to get the total of 3 pizzas</span></p><p><span style="color:#3333ff;">3.(a) Cathy will have $200.00 dollars in her saving account. I got the answer by taking the formula of 20+15(12). I mulitplied 12 by 15 to get 180 then I added her $20.00 dollars to get $200.00 dollars.</span></p><p><span style="color:#3333ff;">(b) If Cathy made a mistake and she had actually had $25.00 dollars instead of $20.00 the formula would be 25+15C= savings account. Then Cathy would have a total of $205.00 dollars for that year. </span></p><p><span style="color:#3333ff;">4.(a) 3n+4n+7= </span></p><p><span style="color:#3333ff;">2n+123(1)+4(1)+7=</span></p><p><span style="color:#3333ff;">2(1)+123+4+7=</span><span style="color:#3333ff;">14</span></p><p><span style="color:#3333ff;">N= 1</span></p><p><span style="color:#3333ff;">b) 8n-(4+9)=11 </span><span style="color:#3333ff;"><br />8(3)-(4+9)=11<br />24-13=11<br />N= 3</span></p><p><span style="color:#3333ff;">(c) (8-3)n+7n+8=</span></p><p><span style="color:#3333ff;">4n+405n+7n+8=</span></p><p><span style="color:#3333ff;">4n+405(4)+7(4)+8=</span></p><p><span style="color:#3333ff;">4(4)+4020+28+8=56</span></p><p><span style="color:#3333ff;">N= 4</span></p>Candynoreply@blogger.com6tag:blogger.com,1999:blog-20385105.post-1148141886911797372006-05-20T08:23:00.000-07:002006-05-22T18:54:20.730-07:00jaymie's growing post for this Tuesday<strong>Question #1: Solve all 3 parts of the problem below</strong><br /><br /><span style="color:#006600;">Jack collects baseball cards. Jack has 180 baseball cards in his collection. At the end of each month Jack buys 25 baseball cards to add to his collection. </span><br /><br /><span style="color:#000099;">a)Create a T-Chart showing how many baseball cards Jack has at the end of the next 4 months.</span><br /><span style="color:#000099;"></span><br /><span style="color:#330033;">Jack will have a total of 280 cards at the end of the next 4 months.</span><br /><span style="color:#000099;"></span><br /><span style="color:#000099;"><a href="http://photos1.blogger.com/blogger/6539/2099/1600/t-chart%20for%20first%20question.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/6539/2099/320/t-chart%20for%20first%20question.jpg" border="0" /></a><br />b)Create an algebraic formula based upon the problem above</span><br /><br />An algebraic formula that can be used for the problem above is:<br /><br /><span style="font-size:180%;">180+25(m)=#of cards</span><br /><br />example: <span style="font-size:180%;">180+25(4)=280 cards</span><br /><br /><p>I started off with multiplying the number of months which is 4 by 25 the number of cards he buys after each month then adding his remaing 180 cards to get a total of 280 cards by then end of the next 4 months.</p><br /><span style="color:#000099;">c)If Jack just turned 8 years old this month and Jack continues to buy the same amount of baseball cards each month, how many baseball cards will jack have when he turns 12?</span><br /><br />Jack will have a total of 1380 cards by the the time he turns 12.<br /><br />I got the answer by first figuring out the difference between 8 and 12 which is 4. So i multiplied 4 by 12 to give me 48 because there are 48 months in 4 years. Then I used the algebraic formula, 180+25(48). All I did was change the variable. So then I multiplied 48 bye 25 to get me 1200, then I added the remaining 180 to get 1380 cards.<br /><br /><br /><strong>Question #2: Use the chart to figure out the questions below.</strong><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/2273/1894/1600/Graph%20-%20Growing%20Post.0.gif"></a><br /><br /><span style="color:#006600;">Jackie is planning on having a pizza party with some of her friends. She is trying to figure out how many pizza’s to order. She knows that each pizza has six slices of pizza.<br /></span><br /><a href="http://photos1.blogger.com/blogger/6539/2099/1600/pizza%20graph.png"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/6539/2099/320/pizza%20graph.png" border="0" /></a><br /><span style="color:#000099;">a)If Jackie thinks that there will be four people at the party (counting herself) how many pizza’s should she order?</span><br /><br />Jackie should order a total of 2 pizzas. She should order 2 pizzas because if you look at the chart and find 4 people it says that there will be 12 slices and if there are 6 slices in each pizza I divide 12 by 6 and that gives me 2 whole pizzas.<br /><span style="color:#000099;"></span><br /><span style="color:#000099;">b)If two more people show up at the party how many more pizza’s does she need to order?<br /></span><br /><strong><span style="color:#000099;"></span></strong>If two more people show up at the party Jackie should order 1 more pizza making a total of 3 pizzas all together. She should order 3 pizzas in total becuase if you look at the chart and find 6 people there will be 18 slices. So divide 18 slices by 6 to get a total of 3 pizzas.<br /><strong></strong><br /><strong>Question #3: Answer the questions below based upon this information</strong><br /><br /><span style="color:#006600;">Kathy has $20 in her savings account. Each month she adds another $15 to her savings account. In order to calculate how much money she will have in one year Kathy has created this algebraic formula: 20 + 15n = Savings amount<br /></span><br /><span style="color:#333399;">a) Calculate how much money Kathy will have in one year </span><br /><p><span style="color:#333399;"><span style="color:#000000;">Cathy will have $200.00 dollars in her saving account. I got that answer by taking her formula of 20+15(12). First I mulitplied 12 by 15 to get 180 then i added her $20.00 dollars to get $200.00 dollars in total. </span></p></span><span style="color:#333399;">b) Suppose Kathy counted wrong and she really has $25 in her account instead of $20. Change the algebraic formula to reflect this miscalculation. </span><br /></span><span style="color:#000000;"></span><br />If Cathy made a mistake and she had actually had $25.00 dollars instead of $20.00 the formula would now be:<br /><br /><span style="font-size:130%;">25+15n=savings account</span><br /><br />Then Cathy would have a total of $205.00 dollars for that 1 year.<br /><br /><strong>Question #4: Solve the following <em>equations</em>. Show all of the steps that are needed.</strong><br /><br />Equations-In a equation the value of the variable is given.<br /><br />a) 3n + 4n + 7 = 2n + 12<br /><br /><span style="color:#666600;">3n+4n+7=2n+12</span><br /><span style="color:#666600;"></span><br /><span style="color:#666600;">3(1)+4(1)+7=2(1)+12</span><br /><span style="color:#666600;"></span><br /><span style="color:#666600;">3+4+7=14</span><br /><span style="color:#666600;"></span><br /><span style="color:#666600;">N= 1<br /></span><br /><br />b) 8n – (4 + 9) = 11<br /><p><span style="color:#006600;">8n-(4+9)=11</span></p><p><span style="color:#006600;">8(3)-(4+9)=11</span></p><p><span style="color:#006600;">24-13=11</span></p><p><span style="color:#006600;">N= 3</span><br /></p>c) (8 – 3 )n + 7n + 8 = 4n + 40<br /><br /><span style="color:#993399;">(8-3)n+7n+8=4n+40</span><br /><span style="color:#993399;"></span><br /><span style="color:#993399;">5n+7n+8=4n+40</span><br /><span style="color:#993399;"></span><br /><span style="color:#993399;">5(4)+7(4)+8=4(4)+40</span><br /><span style="color:#993399;"></span><br /><span style="color:#993399;">20+28+8=56</span><br /><span style="color:#993399;"></span><br /><span style="color:#993399;">N= 4</span>jayhttp://www.blogger.com/profile/12049488223739097242noreply@blogger.com10tag:blogger.com,1999:blog-20385105.post-1147997859189223302006-05-18T16:36:00.000-07:002006-05-18T17:17:39.506-07:00May 18/2006 Scribe notes<span style="color:#cc9933;">For the last couple of days in math, we have been learning about patterns, graphs and algebraic formulas.<br /></span><br />an example of what we have done is...<br /><br /><strong><em><span style="color:#006600;">Jennifer's problem</span></em></strong><br /><span style="color:#000000;"><strong><em></em></strong>Jennifer decides to open up a bank account. She <span style="color:#ff0000;">starts off with $30.00</span> in her account. At the end of <span style="color:#cc33cc;">each month she deposits $18.00</span>. How much will she have <span style="color:#006600;">after 1 year</span>?</span><br /><br />To solve this problem we must first know how much she starts off with( $30.00) thenn how much she puts in each month(<span style="color:#993399;">$18.00</span>)and finally how long will she be putting money in her bank account( <span style="color:#006600;">1 year</span>)<br /><br /><br />We start off by creating an algebraic formula:<br /><a href="http://photos1.blogger.com/blogger/6539/2099/1600/formula.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/6539/2099/320/formula.jpg" border="0" /></a><br /><a href="http://photos1.blogger.com/blogger/6539/2099/1600/jennifer.jpg"><img style="WIDTH: 377px; CURSOR: hand; HEIGHT: 90px" height="103" alt="" src="http://photos1.blogger.com/blogger/6539/2099/320/jennifer.jpg" width="395" border="0" /></a><br /><br /><span style="color:#cc9933;">to get the answer we multiply 12( 1 year) to 18(how much she is depositing) then we add the 30 dollars she has now to give us a total of $246.00 in her bank account.<br /></span><br /><span style="color:#006600;">for people who do not know what a variable is it is a unknown quantity.</span><br /><br /><br /><span style="color:#cc0000;">Then after we did the back of the worksheet Mr.Reece gave to us which said "pattern graFun" at the top.<br /><br />One of the questions that was on the sheet was this question. It asks you to make an algebraic formula, draw the next shape and graph the information.<br /><br /></span><a href="http://photos1.blogger.com/blogger/6539/2099/1600/graphs.jpg"><img style="WIDTH: 408px; CURSOR: hand; HEIGHT: 183px" height="149" alt="" src="http://photos1.blogger.com/blogger/6539/2099/320/graphs.jpg" width="350" border="0" /></a><br /><br />The question is:<br /><br /><strong>Tile Pattern. Draw the next two figures in the pattern of tiles shown above. Show how the number of gray tiles varies with the number of white tiles.</strong><br /><br /><span style="color:#339999;">The two next figures have been already done for you. The tiles start off with a 3 by 3 box meaning that it has 9 tiles. The middle tile is white(1) then the rest are gray(8). The next box is now a 4 by 3 square which means that it now has 12 tiles. The two middle tiles are white and the remaining 10 tiles are gray. In this pattern the top and bottom rows increase by one starting off with 3. Then the white tiles increase by 1 starting from 1. Then we created a t-chart to show what found out. After, we graphed our information.</span><br /><br /><strong>How many gray tiles would be needed for 10 white tiles.</strong><br /><br /><span style="color:#999900;">There will be 32 gray tiles in the tenth figure. There will be 32 because in the figure that has 5 white tiles has 16 gray tiles. So if the figure with the 10 white squares is double the one with the 5 white tiles it will then has 32 gray tiles.</span><br /><span style="color:#999900;"></span><br /><span style="color:#999900;">This worksheet containing 3 different questions will be due tomorrow, may19th/06, 4th period</span><br /><span style="color:#999900;"></span><br /><span style="color:#999900;">After we completed that we started another worksheet that had the same kind of questions on it. That worksheet will be due at the same time as the other worksheet.</span><br /><span style="color:#999900;"></span><br /> <span style="color:#993399;">We have also started something new in class. We have started something called the growing post. The growing post is worth at least 30% of your grade. The growing post is sheets of paper with different question having to do with what we have been learing in class. The will be assigned ever monday and due the next monday. You have one week to complete it. You can either do it on blogger or Hand it in on paper with all the pictures and explanations.</span><br /><span style="color:#993399;"></span><br /><span style="color:#6633ff;">Homework:</span><br /><span style="color:#6633ff;"></span><br /><span style="color:#6633ff;">-worksheet pattern grafun</span><br /><span style="color:#6633ff;">-worksheet patterns 1 problem solving -short snappers</span><br /><span style="color:#6633ff;">-the growing post for the week of may 15 th to 20th due tuesday ma 23rd</span><br /><span style="color:#6633ff;"></span><br /><span style="color:#6633ff;"><strong><em> No school this monday due to victoria day -jaymie-</em></strong></span>jayhttp://www.blogger.com/profile/12049488223739097242noreply@blogger.com5tag:blogger.com,1999:blog-20385105.post-1147863618582176862006-05-17T03:52:00.000-07:002006-05-17T04:03:07.996-07:00Growing Post<strong>Question #1: What is meant by the terms "Rotation Symmetry" and "Reflection Symmetry"? How does this relate to pentominoes? Explain these terms so that anyone who reads your post understands what you mean.<br /></strong><br /><span style="color:#66cccc;">1. Rotation Symmetry- A movement of an object through turning it's figure around(1 degree-360 degrees) it's center point, giving no new shape. That is Rotation symmetry.</span><br /><br /><br /><br /><p><span style="color:#66cccc;"></p></span><a href="http://photos1.blogger.com/blogger/1831/2100/1600/Rotation%20Symmetry.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1831/2100/320/Rotation%20Symmetry.jpg" border="0" /></a><br /><span style="color:#66cccc;">Relfectfion Symmetry- The result of flipping an object. Though it may look 'unique' it is still the same as the object, it was only flipped onto the other side creating a 'reflection'.</span><br /><a href="http://photos1.blogger.com/blogger/1831/2100/1600/Relfection%20Symmetry.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1831/2100/320/Relfection%20Symmetry.jpg" border="0" /></a><br /><br /><span style="color:#000000;"><strong>Question #2: Create a pattern. You must represent this pattern both pictorially (i.e. with a picture or diagram) and with numbers. You must show the first 4 steps of your pattern. </strong><br /><a href="http://photos1.blogger.com/blogger/1831/2100/1600/Growing%20Post.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1831/2100/320/Growing%20Post.jpg" border="0" /></a></span><br /></span><br /><strong>Question #3: Describe in words what is occuring with your pattern and if your pattern has an ending or if it continues on indefinately. Make sure that your explanation is clear enough that the person reading your description could understand your pattern without seeing your diagram.</strong><br /><br /><span style="color:#66cccc;">3. My pattern begins with two blocks, both vertical, and placed under each under. As each step grows, two block get added underneath, making the vertical line larger. This pattern would be be able to continue on forever.</span><br /><br /><strong>Question #4: Create a T-Chart that shows what is happening with your pattern. You must show the first 4 steps of your pattern with the T-chart.<br /></strong><br /><a href="http://photos1.blogger.com/blogger/1831/2100/1600/Gorwing%20Post%202.jpg"><img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1831/2100/320/Gorwing%20Post%202.jpg" border="0" /></a><br /><br />[Pardon me for making this late. My internet hadn't worked on Monday. I understand that I cannot add to this post to earn the marks I could have.]Ariahttp://www.blogger.com/profile/12976271291206028698noreply@blogger.com3tag:blogger.com,1999:blog-20385105.post-1147751242125352372006-05-15T20:27:00.000-07:002006-05-18T10:33:45.346-07:00Janna's Growing Post<strong>Question #1: What is meant by the terms "Rotation Symmetry" and "Reflection Symmetry"? How does this relate to pen</strong><strong>tominoes? Explain these terms so that anyone who reads your post understands what you mean.</strong><br /><br /><span style="color: rgb(51, 51, 255);"><strong>1. <span style="color: rgb(51, 204, 0);">"Rotation symmetry" </span>means that if you can turn or rotate a figure or shape around the center point in less then 360 degrees and the shape doesn’t look different or changed that means that the shape has rotation symmetry.</strong></span><br /><span style="color: rgb(51, 51, 255);"><strong> "<span style="color: rgb(51, 204, 0);">Reflection symmetry</span>" means tha</strong></span><span style="color: rgb(51, 51, 255);"><strong>t a shape or figure w</strong></span><span style="color: rgb(51, 51, 255);"><strong>ill have a mirrored or flipped image of the shape that makes it look unique, but when the shape is flipped opposite they two shapes will look the same. </strong></span><strong style="color: rgb(51, 0, 153);"><br /><br /><span style="color: rgb(51, 204, 0);">Rotation</span> and <span style="color: rgb(51, 204, 0);">reflection</span> symmetry is related to pentominoes because there are only 12 pentominoe shapes,(a few people have found more) but if you use rotation or reflection symmetry, you will see the same pentoninoe shape you craeted but in a different position. The shape will be either rotated or flipped.</strong><br /><strong></strong><br /><strong><span style="color: rgb(51, 51, 255);"><span style="color: rgb(0, 0, 0);"> Question #2: Create a pattern. You must represent this pattern both pictorally and with numbers. You must show the first 4 steps of your pattern.</span></span></strong><br /><strong></strong><br /><strong><span style="color: rgb(255, 0, 0);">2. My pattern is below.<br /></span></strong><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/5982/2100/1600/untitled.3.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/5982/2100/320/untitled.3.jpg" alt="" border="0" /></a><br /><span style="color: rgb(0, 0, 0); font-weight: bold;">Question #3: Describe in words what is occuring with your pattern and if your pattern has an ending or if it continues on indefanetly. Make sure that your explaination is clear</span><span style="color: rgb(0, 0, 0); font-weight: bold;"> enough that the person reading your description could understand your pattern without seeing your diagram.<br /><br /></span><strong style="color: rgb(51, 255, 51); font-weight: bold;"><span style="color: rgb(255, 0, 200);">In my pattern the first step starts with one block. You keep on adding a block for every step. Notice there are the same amount of blocks as there are in the step number. Example: Step number 77, there will be 77 blocks. The pattern doesn't have an end. In step 1 you have one block, in step 2 you add a block. Now you have 2 blocks. In step 3 you add another block, you now have 3 blocks In step 4 you add a block, you now have 4 blocks.<br /><br /><br /><span style="color: rgb(0, 0, 0);">Question #4: create a T-chart that shows what is happening with your Pattern. You must show the first four steps of your pattern with the T-chart.</span></span></strong><strong style="color: rgb(51, 255, 51); font-weight: bold;"><span style="color: rgb(255, 0, 200);"><span style="color: rgb(0, 0, 0);"><br /></span></span></strong><span style="color: rgb(0, 0, 0); font-weight: bold;"><br /></span><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/5982/2100/1600/t%20chart.jpg"><img style="cursor: pointer;" src="http://photos1.blogger.com/blogger/5982/2100/320/t%20chart.jpg" alt="" border="0" /></a>Janna_09noreply@blogger.com4tag:blogger.com,1999:blog-20385105.post-1147747130671787562006-05-15T19:00:00.000-07:002006-05-15T19:38:51.216-07:00Scribe from May 8th - May 12th<strong>Hello, fellow students. I apologize for taking a long to=ime to post the scribe but i was busy and i was making pictures. Here is the scribe below.</strong><br /><strong></strong><br /><span style="color:#3333ff;"><strong>May 8th: We turned in corrections to our Math tests. Also, Mr. Reece gave use five(5) tiles and a sheet of grid paper per person. We were to make shapes using the five tiles. All of the shapes had to touch by one square if not more. The shapes looked like tetris shapes. Here is an example of how and how not to make the shape.</strong></span><br /><strong><span style="color:#3333ff;">I made 12 shapes by using </span><br /></strong><a href="http://photos1.blogger.com/blogger/5982/2100/1600/right.2.jpg"><img style="WIDTH: 204px; CURSOR: hand; HEIGHT: 206px" height="257" alt="" src="http://photos1.blogger.com/blogger/5982/2100/320/right.2.jpg" width="216" border="0" /></a><a href="http://photos1.blogger.com/blogger/5982/2100/1600/untitled.1.jpg"><img style="WIDTH: 175px; CURSOR: hand; HEIGHT: 183px" height="210" alt="" src="http://photos1.blogger.com/blogger/5982/2100/320/untitled.1.jpg" width="226" border="0" /></a><br /><strong><span style="color:#3333ff;">I made twelve (12) different shapes. The shapes I made are below.</span></strong> <a href="http://photos1.blogger.com/blogger/5982/2100/1600/blocks.jpg"><img style="CURSOR: hand" height="240" alt="" src="http://photos1.blogger.com/blogger/5982/2100/320/blocks.jpg" width="283" border="0" /></a><br /><br /><br /><br /><span style="color:#ff0000;"><strong><span style="font-size:130%;">May 9th:</span> Mr.Reece gave us a sheet. the the title was "Constructing Pentominoes". The sheet is constructed below.</strong></span><br /><br /><p><strong><span style="color:#ff0000;"></span></strong></p><p><strong><span style="color:#ff0000;"><span style="font-size:130%;">Constructing Pentominoes</span></span></strong></p><p><strong><span style="color:#ff0000;">Instructions: In your group of 2 or 3 are to construct shapes using a total of 5 tiles. Each of these five tiles must be touching at least one other tile. Once you have constructed a pentominoe you are to record the pentominoe's shape onto your piece of grid paper. You are only to record pentominoes that are unique in nature on your graph paper.</span></strong></p><p><strong><span style="color:#ff0000;">Questions for reflection</span></strong></p><p><strong><span style="color:#ff0000;">1. How many unique pentominoes were you and your partner able to create?</span></strong></p><p><strong><span style="color:#000000;">We answered: We were able to create 12 unique pentominoes.</span></strong></p><p><strong><span style="color:#ff0000;">2. Did you think that you would be able to discover more unique pentominoes if you had more time? How much more time would you have liked?</span></strong></p><p><strong><span style="color:#000000;">We answered: Yes, we do. About one hour of time.</span></strong></p><p><strong><span style="color:#ff0000;">3. When you joined a larger group were you able to discover more unique pentominoes? How many more?</span></strong></p><p><strong><span style="color:#000000;">We answered: Yes, when we joined a larger group we found four more.</span></strong></p><p><span style="color:#ff0000;"><strong>4. Were some of the pentominoes that you traces on your graph paper</strong></span> <span style="color:#ff0000;"><strong>simply reflections or translations of pentominoes that you had already traced?</strong></span> <strong><span style="color:#ff0000;">What made these pentominoes hard to identify? Draw the perntominoes here.</span></strong></p><p><strong><span style="color:#000000;">We answered: yes, they were. They followed the same pattern but the outcome was different.</span></strong></p><p><strong></strong></p><a href="http://photos1.blogger.com/blogger/5982/2100/1600/shapes.jpg"><img style="WIDTH: 593px; CURSOR: hand; HEIGHT: 144px" height="136" alt="" src="http://photos1.blogger.com/blogger/5982/2100/320/shapes.jpg" width="616" border="0" /></a><br /><span style="color:#ff0000;"><strong>5. Did you help identify pentominoes in the largergroup that initially looked different but were simply just reflections or translations of pentominoes that you already had found?</strong></span><br /><p><strong>We answered: Yes, we did.</strong></p>Janna_09noreply@blogger.com6tag:blogger.com,1999:blog-20385105.post-1147743062888068112006-05-15T18:15:00.000-07:002006-05-15T18:31:03.583-07:00Rustine's Growing Post<strong><em><span style="font-family:arial;font-size:85%;">#1. What is meant by the terms "rotation symmetry" and "reflection symmetry?" How does this relate to pentominoes? Explain these terms so that anyone who reads your post understands what you mean.</span></em></strong><br /><strong><em><span style="font-family:Arial;font-size:85%;"></span></em></strong><br /><span style="font-family:arial;font-size:85%;"><strong>rotational symmetry:</strong> is symmetry with respect to some or all rotations, has the ability to turn 360 deegres and still keep its shape.</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><span style="font-family:arial;font-size:85%;"><strong>reflection symmetry:</strong> a symmetric transformation in which a figure is reversed along an axis so that the image looks as though it is in front of a mirror.</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><strong><em>#<span style="font-family:arial;font-size:85%;">2 - QuestionCreate a pattern. You must represent this pattern both pictorially (i.e. with a picture or diagram) and with numbers. You must show the first 4 steps of your pattern.</span></em></strong><br /><strong><em><span style="font-family:Arial;font-size:85%;"></span></em></strong><br /><span style="font-family:Arial;font-size:85%;">The steps are listed in the picture.</span><br /><br /><br /><br /><br />#<span style="font-family:arial;font-size:85%;"><strong><em>3 - QuestionDescribe in words what is occurring with your pattern and if your pattern has an ending or if it continues on indefinitely. Make sure that your explanation is clear enough that the person reading your description could understand your pattern without seeing your diagram.</em></strong></span><br /><strong><em><span style="font-family:Arial;font-size:85%;"></span></em></strong><br /><span style="font-family:Arial;font-size:85%;">In my pattern it looks like the number 'L', you begin with 5 cubes. In my pattern it adds 1 cube to the horizontal part of the letter 'L'. With every step, the horizontal part of my letter gets longer and longer. My pattern never ends .</span><br /><span style="font-family:Arial;font-size:85%;"></span><br /><strong><em>#<span style="font-family:arial;font-size:85%;">4 - QuestionCreate a T-Chart that shows what is happening with your pattern. You must show the first 4 steps of your pattern with the T-chart.</span></em></strong><br /><strong><em><span style="font-family:Arial;font-size:85%;"></span></em></strong><br /><span style="font-family:arial;font-size:85%;">Mr. Reece .. i had some trouble with the pictures . SORRY .</span>bl4z3nhttp://www.blogger.com/profile/13196062698989098094noreply@blogger.com5